Questions in indefinite-integration

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$\int_{{}}^{{}}{\frac{\sqrt{x}}{1+x}dx=}$
$\int_{{}}^{{}}{\frac{\sin x}{\sin x-\cos x}}\ dx=$
$\int{\sqrt{\frac{1+x}{1-x}}\,\,dx=}$
$\int_{{}}^{{}}{\frac{x}{\sqrt{4-{{x}^{4}}}}dx}=$
$\int{\frac{\sin x\,\,dx}{3+4{{\cos }^{2}}x}=}$
The value of $\int_{{}}^{{}}{\frac{dx}{\sqrt{x}\,(x+9)}dx}$ is equal to
${{\int{\left\{ \frac{(\log x-1)}{1+{{(\log x)}^{2}}} \right\}}}^{2}}dx$ is equal to
$\int_{{}}^{{}}{\frac{\sin 2xdx}{1+{{\cos }^{2}}x}}=$
If $\int{\frac{\cos 4x+1}{\cos x-\tan x}}dx=k\,\,\cos 4x+c$ then
If $\int{\frac{1}{x+{{x}^{5}}}dx=f(x)+c}$, then the value of $\int{\frac{{{x}^{4}}}{x+{{x}^{5}}}dx}$ is

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