indefinite-integration

Question: $\int_{{}}^{{}}{\frac{\sqrt{x}}{1+x}dx=}$

1) $\sqrt{x}-{{\tan }^{-1}}\sqrt{x}+c$

2) $2(\sqrt{x}-{{\tan }^{-1}}\sqrt{x})+c$

3) $2(\sqrt{x}+{{\tan }^{-1}}x)+c$

4) $\sqrt{1+x}+c$

Solution:

Explanation: No Explanation

Integration by substitution

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