indefinite-integration

Question: $\int_{{}}^{{}}{\frac{\sin x}{\sin x-\cos x}}\ dx=$

1) $\frac{1}{2}\log (\sin x-\cos x)+x+c$

2) $\frac{1}{2}[\log (\sin x-\cos x)+x]+c$

3) $\frac{1}{2}\log (\cos x-\sin x)+x+c$

4) $\frac{1}{2}[\log (\cos x-\sin x)+x]+c$

Solution:

Explanation: No Explanation

Integration by substitution

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