indefinite-integration

Question: $\int_{{}}^{{}}{\frac{1}{\sqrt{x}}}\sin \sqrt{x}\ dx=$



1) $-\frac{1}{2}\cos \sqrt{x}+c$
2) $-2\cos \sqrt{x}+c$
3) $\frac{1}{2}\cos \sqrt{x}+c$
4) $2\cos \sqrt{x}+c$
Solution: Explanation: No Explanation
Integration by substitution

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