indefinite-integration

Question: $\int_{{}}^{{}}{{{\sec }^{4}}x\tan x\ dx=}$



1) $\frac{1}{4}{{\sec }^{4}}x+c$
2) $4{{\sec }^{4}}x+c$
3) $\frac{{{\sec }^{3}}x}{3}+c$
4) $3{{\sec }^{3}}x+c$
Solution: Explanation: No Explanation
Integration by substitution

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