indefinite-integration

Question: $\int_{{}}^{{}}{{{e}^{-x}}\text{cose}{{\text{c}}^{2}}(2{{e}^{-x}}+5)}\ dx=$

1) $\frac{1}{2}\cot (2{{e}^{-x}}+5)+c$

2) $-\frac{1}{2}\cot (2{{e}^{-x}}+5)+c$

3) $2\cot (2{{e}^{-x}}+5)+c$

4) $-2\cot (2{{e}^{-x}}+5)+c$

Solution:

Explanation: No Explanation

Integration by substitution

Rate this question:

★ ★ ★ ★ ★

Average rating: (0 votes)