indefinite-integration

Question: $\int_{{}}^{{}}{\frac{dx}{\sqrt{{{x}^{2}}+{{a}^{2}}}}}$ is equal to

1) $\frac{1}{2}x\sqrt{{{x}^{2}}+{{a}^{2}}}+\frac{1}{2}{{a}^{2}}\log (x+\sqrt{{{x}^{2}}+{{a}^{2}}})+c$

2) $\frac{1}{2}\log ({{x}^{2}}+{{a}^{2}})+c$

3) $\log (x+\sqrt{{{x}^{2}}+{{a}^{2}}})+c$

4) $\log (x-\sqrt{{{x}^{2}}+{{a}^{2}}})+c$

Solution:

Explanation: No Explanation

Fundamental integration

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