Questions in indefinite-integration

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Let $f(x)=\int{\frac{{{x}^{2}}dx}{(1+{{x}^{2}})\,\left( 1+\sqrt{1+{{x}^{2}}} \right)}}$and $f(0)=0$, then the value of $f(1)$ be
$\int{\sqrt{{{e}^{x}}-1}}dx=$
$\int{\frac{dx}{\sin (x-a)\sin (x-b)}}$ is
$\int{\frac{(\sin \theta +\cos \theta )}{\sqrt{\sin 2\theta }}}d\theta =$
$\int{{{\cos }^{-3/7}}}x{{\sin }^{-11/7}}x\,\,dx=$
$\int_{{}}^{{}}{x{{\sec }^{2}}x\ dx}=$
$\int_{{}}^{{}}{\sin (\log x)dx=}$
If $\int_{{}}^{{}}{x\sin xdx=-x\cos x+A}$, then $A=$
$\int_{{}}^{{}}{x\log xdx=}$
$\int_{{}}^{{}}{x\cos x\ dx=}$

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