indefinite-integration

Question: ${{\int{\left\{ \frac{(\log x-1)}{1+{{(\log x)}^{2}}} \right\}}}^{2}}dx$ is equal to

1) $\frac{x{{e}^{x}}}{1+{{x}^{2}}}+c$

2) $\frac{x}{{{(\log x)}^{2}}+1}+C$

3) $\frac{\log x}{{{(\log x)}^{2}}+1}+c$

4) $\frac{x}{{{x}^{2}}+1}+c$

Solution:

Explanation: No Explanation

Integration by substitution

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