indefinite-integration

Question: $\int_{{}}^{{}}{\frac{\sin 2xdx}{1+{{\cos }^{2}}x}}=$

1) $\frac{1}{2}\log (1+{{\cos }^{2}}x)+c$

2) $2\log (1+{{\cos }^{2}}x)+c$

3) $\frac{1}{2}\log (1+\cos 2x)+c$

4) $-\log (1+{{\cos }^{2}}x)+c$

Solution:

Explanation: No Explanation

Integration by substitution

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