indefinite-integration

Question: The value of $\int_{{}}^{{}}{\frac{dx}{\sqrt{x}\,(x+9)}dx}$ is equal to

1) ${{\tan }^{-1}}\sqrt{x}$

2) ${{\tan }^{-1}}\left( \frac{\sqrt{x}}{3} \right)$

3) $\frac{2}{3}{{\tan }^{-1}}\sqrt{x}$

4) $\frac{2}{3}{{\tan }^{-1}}\left( \frac{\sqrt{x}}{3} \right)$

Solution:

Explanation: No Explanation

Integration by substitution

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