Questions tagged 'Differentiation by substitution'

• If $y=\sin (2{{\sin }^{-1}}x),$then $\frac{dy}{dx}=$
  Category: differentiation | Tags: Differentiation by substitution, Higher order derivatives
• If $y={{\cos }^{-1}}\left( \frac{3\cos x+4\sin x}{5} \right)$, then $\frac{dy}{dx}=$
  Category: differentiation | Tags: Differentiation by substitution, Higher order derivatives
• $\frac{d}{dx}{{\cos }^{-1}}\frac{x-{{x}^{-1}}}{x+{{x}^{-1}}}$=
  Category: differentiation | Tags: Differentiation by substitution, Higher order derivatives
• If $y={{\sin }^{-1}}\frac{2x}{1+{{x}^{2}}}+{{\sec }^{-1}}\frac{1+{{x}^{2}}}{1-{{x}^{2}}}$, then $\frac{dy}{dx}$=
  Category: differentiation | Tags: Differentiation by substitution, Higher order derivatives
• If $y={{\tan }^{-1}}\frac{x}{1+\sqrt{1-{{x}^{2}}}}+\sin \left\{ 2{{\tan }^{-1}}\sqrt{\left( \frac{1-x}{1+x} \right)} \right\}$,then $\frac{dy}{dx}$=
  Category: differentiation | Tags: Differentiation by substitution, Higher order derivatives
• If $y={{\sin }^{-1}}\frac{2x}{1+{{x}^{2}}},$where $0<x<1$and $0<y<\frac{\pi }{2},$ then $\frac{dy}{dx}=$
  Category: differentiation | Tags: Differentiation by substitution, Higher order derivatives
• $\frac{d}{dx}{{\tan }^{-1}}\frac{x}{\sqrt{{{a}^{2}}-{{x}^{2}}}}=$
  Category: differentiation | Tags: Differentiation by substitution, Higher order derivatives
• $\frac{d}{dx}{{\cos }^{-1}}\sqrt{\frac{1+{{x}^{2}}}{2}}=$
  Category: differentiation | Tags: Differentiation by substitution, Higher order derivatives
• $\frac{d}{dx}{{\tan }^{-1}}\left[ \frac{3{{a}^{2}}x-{{x}^{3}}}{a({{a}^{2}}-3{{x}^{2}})} \right]$at $x=0$is
  Category: differentiation | Tags: Differentiation by substitution, Higher order derivatives
• If $\sqrt{1-{{x}^{2}}}+\sqrt{1-{{y}^{2}}}=a(x-y)$, then $\frac{dy}{dx}=$
  Category: differentiation | Tags: Differentiation by substitution, Higher order derivatives

Back to Home