differentiation

Question: If $y={{\sin }^{-1}}\frac{2x}{1+{{x}^{2}}},$where $0<x<1$and $0<y<\frac{\pi }{2},$ then $\frac{dy}{dx}=$



1) $\frac{2}{1+{{x}^{2}}}$
2) $\frac{2x}{1+{{x}^{2}}}$
3) $\frac{-2}{1+{{x}^{2}}}$
4) $\frac{-x}{1+{{x}^{2}}}$
Solution: Explanation: No Explanation
Differentiation by substitution Higher order derivatives

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