differentiation

Question: If $y={{\sin }^{-1}}\frac{2x}{1+{{x}^{2}}}+{{\sec }^{-1}}\frac{1+{{x}^{2}}}{1-{{x}^{2}}}$, then $\frac{dy}{dx}$=

1) $\frac{4}{1-{{x}^{2}}}$

2) $\frac{1}{1+{{x}^{2}}}$

3) $\frac{4}{1-{{x}^{2}}}$

4) $\frac{-4}{1+{{x}^{2}}}$

Solution:

Explanation: No Explanation

Differentiation by substitution Higher order derivatives

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