definite-integral

Question: The area formed by triangular shaped region bounded by the curves $y=\sin x,\,y=\cos x$ and $x=0$ is



1) $x={{y}^{2}}$
2) 1
3) $\sqrt{2}$
4) $1+\sqrt{2}$
Solution: Explanation: No Explanation
Area bounded by region Volume and surface area of solids of revolution

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