definite-integral

Question: The part of straight line $y=x+1$ between $x=2$ and $x=3$ is revolved about x-axis, then the curved surface of the solid thus generated is



1) $37\pi /3$
2) $7\pi \sqrt{2}$
3) $37\pi $
4) $y={{x}^{2}}$
Solution: Explanation: No Explanation
Area bounded by region Volume and surface area of solids of revolution

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