definite-integral

Question: The area of smaller part between the circle ${{x}^{2}}+{{y}^{2}}=4$and the line $x=1$ is



1) $\frac{4\pi }{3}-\sqrt{3}$
2) $\frac{8\pi }{3}-\sqrt{3}$
3) $\frac{4\pi }{3}+\sqrt{3}$
4) $\frac{5\pi }{3}+\sqrt{3}$
Solution: Explanation: No Explanation
Area bounded by region Volume and surface area of solids of revolution

Rate this question:

Average rating: (0 votes)

Previous Question Next Question