definite-integral

Question: The value of $\int_{0}^{1}{\frac{{{x}^{4}}+1}{{{x}^{2}}+1}\,dx}$ is



1) $\frac{1}{6}(3\pi -4)$
2) $\frac{1}{6}(3-4\pi )$
3) $\frac{1}{6}(3\pi +4)$
4) $\frac{1}{6}(3+4\pi )$
Solution: Explanation: No Explanation
Fundamental definite integration Definite integration by substitution

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