definite-integral

Question: If $P=\int_{0}^{3\pi }{f({{\cos }^{2}}x)dx}\,\,\text{and}\,\,Q=\int_{0}^{\pi }{f({{\cos }^{2}}x)dx}$, then



1) $P-Q=0$
2) $P-2Q=0$
3) $P-3Q=0$
4) $P-5Q=0$
Solution: Explanation: No Explanation
Properties of definite integration

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