definite-integral

Question: If the area bounded by $y=a{{x}^{2}}$and $x=a{{y}^{2}}$, $a>0$, is 1, then $a=$



1) 1
2) $\frac{1}{\sqrt{3}}$
3) $\frac{1}{3}$
4) None of these
Solution: Explanation: No Explanation
Area bounded by region Volume and surface area of solids of revolution

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