definite-integral

Question: The area bounded by the curve $y=f(x)$, x-axis and ordinates x = 1 and $x=b$is $\frac{5}{24}\pi $, then $f(x)$ is



1) $3(x-1)\cos (3x+4)+\sin (3x+4)$
2) $(b-1)\sin (3x+4)+3\cos (3x+4)$
3) $(b-1)\cos (3x+4)+3\sin (3x+4)$
4) None of these
Solution: Explanation: No Explanation
Area bounded by region Volume and surface area of solids of revolution

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