definite-integral

Question: The area between the parabola ${{y}^{2}}=4ax$and ${{x}^{2}}=8ay$ is



1) $\frac{8}{3}{{a}^{2}}$
2) $\frac{4}{3}{{a}^{2}}$
3) $\frac{32}{3}{{a}^{2}}$
4) $\frac{16}{3}{{a}^{2}}$
Solution: Explanation: No Explanation
Area bounded by region Volume and surface area of solids of revolution

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