definite-integral

Question: $\int_{0}^{1}{f(1-x)\,dx}$ has the same value as the integral



1) $\int_{0}^{1}{f(x)\,dx}$
2) $\int_{0}^{1}{f(-x)\,dx}$
3) $\int_{0}^{1}{f(x-1)\,dx}$
4) $\int_{-1}^{1}{f(x)\,dx}$
Solution: Explanation: No Explanation
Properties of definite integration

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