definite-integral

Question: $\int_{0}^{a}{{{x}^{4}}\sqrt{{{a}^{2}}-{{x}^{2}}}}\,dx=$



1) $\frac{\pi }{32}$
2) $\frac{\pi }{32}{{a}^{6}}$
3) $\frac{\pi }{16}{{a}^{6}}$
4) $\frac{\pi }{8}{{a}^{6}}$
Solution: Explanation: No Explanation
Summation of series by definite Integration

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