definite-integral

Question: Area under the curve $y=\sin 2x+\cos 2x$ between $x=0$ and $x=\frac{\pi }{4},$ is



1) 2 sq. unit
2) 1 sq. unit
3) 3 sq. unit
4) 4 sq. unit
Solution: Explanation: No Explanation
Area bounded by region Volume and surface area of solids of revolution

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