definite-integral

Question: The value of $\int_{0}^{1}{\frac{dx}{{{e}^{x}}+{{e}^{-x}}}}$ is

1) ${{\tan }^{-1}}\left( \frac{1-e}{1+e} \right)$

2) ${{\tan }^{-1}}\left( \frac{e-1}{e+1} \right)$

3) $\frac{\pi }{4}$

4) ${{\tan }^{-1}}e+\frac{\pi }{4}$

Solution:

Explanation: No Explanation

Fundamental definite integration Definite integration by substitution

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