definite-integral

Question: $\int_{\,0}^{\,\pi /2}{\{x-[\sin x]\}\,dx}$ is equal to



1) $\frac{{{\pi }^{2}}}{8}$
2) $\frac{{{\pi }^{2}}}{8}-1$
3) $\frac{{{\pi }^{2}}}{8}-2$
4) None of these
Solution: Explanation: No Explanation
Properties of definite integration

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