definite-integral

Question: Area under the curve $y=\sqrt{3x+4}$ between $x=0$ and $x=4,$ is



1) $\frac{56}{9}$ sq. unit
2) $\frac{64}{9}$ sq. unit
3) 8 sq. unit
4) None of these
Solution: Explanation: No Explanation
Area bounded by region Volume and surface area of solids of revolution

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