definite-integral

Question: $\int_{\,0}^{\,\infty }{\,\log \left( x+\frac{1}{x} \right)\frac{dx}{1+{{x}^{2}}}}$ is equal to



1) $\pi \log 2$
2) $-\pi \log 2$
3) $(\pi /2)\log 2$
4) $-(\pi /2)\log 2$
Solution: Explanation: No Explanation
Summation of series by definite Integration

Rate this question:

Average rating: (0 votes)

Previous Question Next Question