definite-integral

Question: The area bounded by the circle ${{x}^{2}}+{{y}^{2}}=4,$ line $x=\sqrt{3}y$ and $x-$axis lying in the first quadrant, is



1) $\frac{\pi }{2}$
2) $\frac{\pi }{4}$
3) $\frac{\pi }{3}$
4) $\pi $
Solution: Explanation: No Explanation
Area bounded by region Volume and surface area of solids of revolution

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