definite-integral

Question: The value of the integral $\int_{-1}^{1}{\frac{d}{dx}\left( {{\tan }^{-1}}\frac{1}{x} \right)}\,dx$ is



1) $\frac{\pi }{2}$
2) $\frac{\pi }{4}$
3) $-\frac{\pi }{2}$
4) None of these
Solution: Explanation: No Explanation
Summation of series by definite Integration

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