definite-integral

Question: $\int_{-\pi /2}^{\pi /2}{{{\sin }^{2}}x\,dx=}$

1) $\pi $

2) $\frac{\pi }{2}$

3) $\frac{\pi }{2}-\frac{1}{2}$

4) $\pi -1$

Solution:

Explanation: No Explanation

Summation of series by definite Integration

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