indefinite-integration

Question: ${{I}_{1}}=\int{{{\sin }^{-1}}x\,\,dx}$ and ${{I}_{2}}=\int{{{\sin }^{-1}}\sqrt{1-{{x}^{2}}}}dx$then

1) ${{I}_{1}}={{I}_{2}}$

2) ${{I}_{2}}=\pi /2{{I}_{1}}$

3) ${{I}_{1}}+{{I}_{2}}=\pi /2x$

4) ${{I}_{1}}+{{I}_{2}}=\pi /2$

Solution:

Explanation: No Explanation

Integration by parts

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