indefinite-integration

Question: $\int_{{}}^{{}}{{{e}^{\sqrt{x}}}\ dx}$ is equal to (A is an arbitrary constant)

1) ${{e}^{\sqrt{x}}}+A$

2) $\frac{1}{2}{{e}^{\sqrt{x}}}+A$

3) $2(\sqrt{x}-1){{e}^{\sqrt{x}}}+A$

4) $2(\sqrt{x}+1){{e}^{\sqrt{x}}}+A$

Solution:

Explanation: No Explanation

Integration by parts

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