indefinite-integration

Question: $\int_{{}}^{{}}{\frac{{{a}^{x}}}{\sqrt{1-{{a}^{2x}}}}dx=}$

1) $\frac{1}{\log a}{{\sin }^{-1}}{{a}^{x}}+c$

2) ${{\sin }^{-1}}{{a}^{x}}+c$

3) $\frac{1}{\log a}{{\cos }^{-1}}{{a}^{x}}+c$

4) ${{\cos }^{-1}}{{a}^{x}}+c$

Solution:

Explanation: No Explanation

Integration by substitution

Rate this question:

★ ★ ★ ★ ★

Average rating: (0 votes)