indefinite-integration

Question: $\int{\frac{{{x}^{2}}}{{{x}^{2}}+4}\,\,dx}$ equals to

1) $x-2{{\tan }^{-1}}(x/2)+c$

2) $x+2{{\tan }^{-1}}(x/2)+c$

3) $x-4{{\tan }^{-1}}(x/2)+c$

4) $x+4{{\tan }^{-1}}(x/2)+c$

Solution:

Explanation: No Explanation

Fundamental integration

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