indefinite-integration

Question: $\int_{{}}^{{}}{\log (x+1)dx=}$



1) $(x+1)\log (x+1)-x+c$
2) $(x+1)\log (x+1)+x+c$
3) $(x-1)\log (x+1)-x+c$
4) $(x-1)\log (x+1)+x+c$
Solution: Explanation: No Explanation
Integration by parts

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