indefinite-integration

Question: $\int_{{}}^{{}}{\frac{2x}{{{(2x+1)}^{2}}}dx=}$



1) $\frac{1}{2}\log (2x+1)+\frac{1}{2(2x+1)}+c$
2) $\frac{1}{2}\log (2x+1)-\frac{1}{2(2x+1)}+c$
3) $2\log (2x+1)+\frac{1}{2(2x+1)}+c$
4) $2\log (2x+1)-\frac{1}{2(2x+1)}+c$
Solution: Explanation: No Explanation
Fundamental integration

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