indefinite-integration

Question: The value of $\int{\frac{\log x}{{{(x+1)}^{2}}}dx}$ is



1) $\frac{-\log x}{x+1}+\log x-\log \,(x+1)$
2) $\frac{\log x}{\left( x+1 \right)}+\log x-\log \,(x+1)$
3) $\frac{\log x}{x+1}-\log x-\log \,(x+1)$
4) $\frac{-\log x}{x+1}-\log x-\log \,(x+1)$
Solution: Explanation: No Explanation
Integration by parts

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