indefinite-integration

Question: $\int_{{}}^{{}}{{{\sin }^{-1}}x\ dx}$is equal to

1) $\frac{1}{\sqrt{1-{{x}^{2}}}}+c$

2) $x{{\sin }^{-1}}x-\sqrt{1-{{x}^{2}}}+c$

3) ${{\cos }^{-1}}x+c$

4) $x{{\sin }^{-1}}x+\sqrt{1-{{x}^{2}}}+c$

Solution:

Explanation: No Explanation

Integration by parts

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