indefinite-integration

Question: $\int_{{}}^{{}}{\frac{t}{{{e}^{3{{t}^{2}}}}}\ dt=}$



1) $\frac{1}{6}{{e}^{3{{t}^{2}}}}+c$
2) $-\frac{1}{6}{{e}^{3{{t}^{2}}}}+c$
3) $\frac{1}{6}{{e}^{-3{{t}^{2}}}}+c$
4) $-\frac{1}{6}{{e}^{-3{{t}^{2}}}}+c$
Solution: Explanation: No Explanation
Integration by substitution

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