indefinite-integration

Question: $\int_{{}}^{{}}{\frac{{{x}^{2}}+1}{x({{x}^{2}}-1)}\ dx}$ is equal to

1) $\log \frac{{{x}^{2}}-1}{x}+c$

2) $-\log \frac{{{x}^{2}}-1}{x}+c$

3) $\log \frac{x}{{{x}^{2}}+1}+c$

4) $-\log \frac{x}{{{x}^{2}}+1}+c$

Solution:

Explanation: No Explanation

Integration by substitution

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