indefinite-integration

Question: $\int_{{}}^{{}}{\frac{x}{\sqrt{4-{{x}^{4}}}}dx}=$

1) ${{\cos }^{-1}}\frac{{{x}^{2}}}{2}$

2) $\frac{1}{2}{{\cos }^{-1}}\frac{{{x}^{2}}}{2}$

3) ${{\sin }^{-1}}\frac{{{x}^{2}}}{2}$

4) $\frac{1}{2}{{\sin }^{-1}}\frac{{{x}^{2}}}{2}$

Solution:

Explanation: No Explanation

Integration by substitution

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