indefinite-integration

Question: $\int_{{}}^{{}}{\frac{2x{{\tan }^{-1}}{{x}^{2}}}{1+{{x}^{4}}}}\ dx=$

1) ${{[{{\tan }^{-1}}{{x}^{2}}]}^{2}}+c$

2) $\frac{1}{2}{{[{{\tan }^{-1}}{{x}^{2}}]}^{2}}+c$

3) $2{{[{{\tan }^{-1}}{{x}^{2}}]}^{2}}+c$

4) None of these

Solution:

Explanation: No Explanation

Integration by substitution

Rate this question:

★ ★ ★ ★ ★

Average rating: (0 votes)