indefinite-integration

Question: $\int_{{}}^{{}}{\frac{{{x}^{3}}}{\sqrt{1-{{x}^{8}}}}dx=}$

1) $\frac{1}{2}{{\sin }^{-1}}({{x}^{4}})+c$

2) $\frac{1}{3}{{\sin }^{-1}}({{x}^{4}})+c$

3) $\frac{1}{4}{{\sin }^{-1}}({{x}^{4}})+c$

4) None of these

Solution:

Explanation: No Explanation

Integration by substitution

Rate this question:

★ ★ ★ ★ ★

Average rating: (0 votes)