indefinite-integration

Question: $\int_{{}}^{{}}{[f(x)g''(x)-f''(x)g(x)]}\ dx$ is equal to



1) $\frac{f(x)}{g'(x)}$
2) $f'(x)g(x)-f(x)g'(x)$
3) $f(x)g'(x)-f'(x)g(x)$
4) $f(x)g'(x)+f'(x)g(x)$
Solution: Explanation: No Explanation
Integration by parts

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