indefinite-integration

Question: $\int_{{}}^{{}}{(x+3){{({{x}^{2}}+6x+10)}^{9}}\ dx}$ equals



1) $\frac{1}{20}{{({{x}^{2}}+6x+10)}^{10}}+c$
2) $\frac{1}{20}{{(x+3)}^{2}}{{({{x}^{2}}+6x+10)}^{10}}+c$
3) $\frac{1}{16}{{({{x}^{2}}+6x+10)}^{8}}+c$
4) $\frac{1}{38}{{(x+3)}^{19}}+\frac{1}{2}(x+3)+c$
Solution: Explanation: No Explanation
Integration by substitution

Rate this question:

Average rating: (0 votes)

Previous Question Next Question