indefinite-integration

Question: The value of $\int_{{}}^{{}}{\left( 1+\frac{1}{{{x}^{2}}} \right)\ {{e}^{\left( x-\frac{1}{x} \right)}}}\ dx$ equals

1) ${{e}^{x-\frac{1}{x}}}+c$

2) ${{e}^{x+\frac{1}{x}}}+c$

3) ${{e}^{{{x}^{2}}-\frac{1}{x}}}+c$

4) ${{e}^{{{x}^{2}}+\frac{1}{{{x}^{2}}}}}+c$

Solution:

Explanation: No Explanation

Integration by substitution

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