indefinite-integration

Question: $\int_{{}}^{{}}{\frac{{{\sec }^{2}}x}{1+\tan x}\ dx=}$

1) $\log (\cos x+\sin x)+c$

2) $\log ({{\sec }^{2}}x)+c$

3) $\log (1+\tan x)+c$

4) $-\frac{1}{{{(1+\tan x)}^{2}}}+c$

Solution:

Explanation: No Explanation

Integration by substitution

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