indefinite-integration

Question: $\int_{{}}^{{}}{\frac{{{e}^{2x}}-1}{{{e}^{2x}}+1}}\ dx=$

1) $\frac{{{e}^{2x}}-1}{{{e}^{2x}}+1}+c$

2) $\log ({{e}^{2x}}+1)-x+c$

3) $\log ({{e}^{2x}}+1)+c$

4) None of these

Solution:

Explanation: No Explanation

Integration by substitution

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